Let ( <mi mathvariant="normal">&#x03A9;<!-- Ω --> , &#x03BC;<!-- μ --> ) be a meas

antennense

antennense

Answered question

2022-07-09

Let ( Ω , μ ) be a measure space. Suppose that ( f n ) converges almost everywhere to some function f where each f n belongs to L ( Ω ). Suppose that sup n f n < .
Do we have f L ( Ω ) ?

Answer & Explanation

Yair Boyle

Yair Boyle

Beginner2022-07-10Added 10 answers

Yes.
Let C = sup f n and denote by Ω n the set of x for which | f n ( x ) | f n C. Let Ω be the set of x for which f n ( x ) converges to f ( x ).
Then we have for x Ω n Ω n ,
| f ( x ) | = lim n | f n ( x ) | C
and the set Ω n Ω n is a set with complement of zero measure.

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?