How can I show using the monotone convergence theorem that the Lebesgue integral <msubsup> &

Keenan Santos

Keenan Santos

Answered question

2022-07-15

How can I show using the monotone convergence theorem that the Lebesgue integral
0 sin ( x ) x d x
does not exist?

Answer & Explanation

escampetaq5

escampetaq5

Beginner2022-07-16Added 12 answers

Recall that f is (Lebesgue) integrable if and only if | f | is Lebesgue integrable. Now, we may write
f n ( x ) = k = 0 n | sin x | x χ [ k π , ( k + 1 ) π ]
so that f n f n + 1 and f n f pointwise, where f ( x ) = | sin x | x . We may then estimate the integral of each term in the sum via:
2 ( k + 1 ) π = k π ( k + 1 ) π | sin x | ( k + 1 ) π d x k π ( k + 1 ) π | sin x | x d x
So that by the monotone convergence theorem,
0 | sin x | x d x = lim n 0 f n d x k = 0 2 ( k + 1 ) π =
Which implies that the Lebesgue integral of sin x x does not exist.

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