If ( x + 2 ) 2 = 9 and ( y + 3 ) 2 = 25 , then what is the maximum value of x y is?

Step 1 ( x + 2 ) 2 = 9 ⇒ x + 2 = ± 3 ⇒ x = 1 or -5and ( y + 3 ) 2 = 25 ⇒ y + 3 = ± 5 ⇒ y = 2 or -8Therefore, maximum value of x y = − 5 − 8 = 5 8

Get the answer to "If ( x + 2 ) 2 =..."

Pierre Holmes

2022-07-16

(x + 2) 2 = 9

and

(y + 3) 2 = 25

, then what is the maximum value of

\frac{x}{y}

is?

Clarissa Adkins

Beginner2022-07-17Added 16 answers

Step 1

(x + 2)^{2} = 9 \Rightarrow x + 2 = \pm 3 \Rightarrow x = 1

or -5
and

(y + 3)^{2} = 25

\Rightarrow y + 3 = \pm 5 \Rightarrow y = 2

or -8
Therefore, maximum value of

\frac{x}{y} = \frac{- 5}{- 8} = \frac{5}{8}

Quessyrutty6w

Beginner2022-07-18Added 3 answers

Step 1

(x + 2)^{2} = 9

(x + 2) = 3 - (x + 2) = 3

x = 1

and -5
and

(y + 3) 2 = 25

(y + 3) = 5 - (y + 3) = 5

y = 2

and -8
then, max from x and y is

x = 1, y = 2

so answer

\frac{x}{y} = \frac{1}{2}

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