The second of three negative numbers is 6 less than the first negative number. The third negative number is three times the second. Find the set of all possible third numbers given that twice the sum of the first two numbers is greater than the third.

Parker Bird

Parker Bird

Answered question

2022-07-26

The second of three negative numbers is 6 less than the first negative number. The third negative number is three times the second. Find the set of all possible third numbers given that twice the sum of the first two numbers is greater than the third.

Answer & Explanation

i4epdp

i4epdp

Beginner2022-07-27Added 12 answers

x , x-6 , 3(x-6)
2(x+x-6) > 3(x-6)
4x - 12 > 3x - 18
x > -6
so the set is : {x | -6 < x < 0}

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