Haley Madden

2022-07-24

a) In 5 years, twice a puppy's current age will be equal to or greater than 15. What is the least integer that satisfies the inequality $2x+5\ge 15?$

b) To the nearest square meter, what is the area of the figure below?

c) The Philippine Trench in the Pacific Ocean is 10.05 kilometers deep. The Brazil Basin in the Atlantic Ocean is 6.12 kilimeters deep. To the nearest hundredth of a kilometer, how many kilometers deeper than the Brazil Basin is the Philippine Trench?

d) A supermarket is having a sale on canned foods. The sale includes 12 cans of soup for $\mathrm{\$}10.65$ . What is the unit price per can of soup to the nearest cent?

b) To the nearest square meter, what is the area of the figure below?

c) The Philippine Trench in the Pacific Ocean is 10.05 kilometers deep. The Brazil Basin in the Atlantic Ocean is 6.12 kilimeters deep. To the nearest hundredth of a kilometer, how many kilometers deeper than the Brazil Basin is the Philippine Trench?

d) A supermarket is having a sale on canned foods. The sale includes 12 cans of soup for $\mathrm{\$}10.65$ . What is the unit price per can of soup to the nearest cent?

Cheyanne Charles

Beginner2022-07-25Added 13 answers

Step 1

a) The leart integer canbe find as undear $\xf7$

$2x+5\ge 15\phantom{\rule{0ex}{0ex}}2x+\text{\u29f8}5-\text{\u29f8}5\ge 15-5\dots \text{Subtractiny 5 both side}\phantom{\rule{0ex}{0ex}}2x\ge 10\dots \text{Now dividing by 2 (both side)}\phantom{\rule{0ex}{0ex}}\frac{\text{\u29f8}2x}{\text{\u29f8}2}\ge \frac{\text{\u29f8}{10}^{5}}{\text{\u29f8}2}\phantom{\rule{0ex}{0ex}}x\ge 5\phantom{\rule{0ex}{0ex}}\therefore \text{The Answer is 5}$

Step 2

b) The area of the fig

The area of

triangle $=\frac{1}{\text{\u29f8}2}\times \text{base}\times \text{hei}$

$\text{i.e}=\frac{1}{\text{\u29f8}2}\times \text{\u29f8}{12}^{6}\times 18\phantom{\rule{0ex}{0ex}}=108{m}^{2}$

Now area of rectangle $=ADEB=P\times B$

$i.e\text{}Ar=P\times B\phantom{\rule{0ex}{0ex}}=18\times 15\phantom{\rule{0ex}{0ex}}=270{m}^{2}\phantom{\rule{0ex}{0ex}}\text{Total area}=Ar.of\text{}\mathrm{\u25b3}ABC+Ar.ofRect\phantom{\rule{0ex}{0ex}}=108+270\phantom{\rule{0ex}{0ex}}=378{m}^{2}$

a) The leart integer canbe find as undear $\xf7$

$2x+5\ge 15\phantom{\rule{0ex}{0ex}}2x+\text{\u29f8}5-\text{\u29f8}5\ge 15-5\dots \text{Subtractiny 5 both side}\phantom{\rule{0ex}{0ex}}2x\ge 10\dots \text{Now dividing by 2 (both side)}\phantom{\rule{0ex}{0ex}}\frac{\text{\u29f8}2x}{\text{\u29f8}2}\ge \frac{\text{\u29f8}{10}^{5}}{\text{\u29f8}2}\phantom{\rule{0ex}{0ex}}x\ge 5\phantom{\rule{0ex}{0ex}}\therefore \text{The Answer is 5}$

Step 2

b) The area of the fig

The area of

triangle $=\frac{1}{\text{\u29f8}2}\times \text{base}\times \text{hei}$

$\text{i.e}=\frac{1}{\text{\u29f8}2}\times \text{\u29f8}{12}^{6}\times 18\phantom{\rule{0ex}{0ex}}=108{m}^{2}$

Now area of rectangle $=ADEB=P\times B$

$i.e\text{}Ar=P\times B\phantom{\rule{0ex}{0ex}}=18\times 15\phantom{\rule{0ex}{0ex}}=270{m}^{2}\phantom{\rule{0ex}{0ex}}\text{Total area}=Ar.of\text{}\mathrm{\u25b3}ABC+Ar.ofRect\phantom{\rule{0ex}{0ex}}=108+270\phantom{\rule{0ex}{0ex}}=378{m}^{2}$

Urijah Estes

Beginner2022-07-26Added 5 answers

Step 1

c) Solve: The philippine trench = 10.05 km

The Brazil basin = 6.12 km

Therefore the philippine trench is deeper then Brasil basin by

$=10.05-6.12\phantom{\rule{0ex}{0ex}}=3.93km$

i.e 3.93 km Answer

Step 2

Solve:

Since: $\mathrm{\$}=100\text{}\text{cent}\phantom{\rule{0ex}{0ex}}\therefore \mathrm{\$}10.65=10.65\times 100\phantom{\rule{0ex}{0ex}}=1065\text{}\text{cent}$

Now: 12 cans of cost =1065

$\therefore =\frac{1065}{12}=8875\phantom{\rule{0ex}{0ex}}\therefore \text{one can of soup}=8875\phantom{\rule{0ex}{0ex}}\text{our 89 cent}$

c) Solve: The philippine trench = 10.05 km

The Brazil basin = 6.12 km

Therefore the philippine trench is deeper then Brasil basin by

$=10.05-6.12\phantom{\rule{0ex}{0ex}}=3.93km$

i.e 3.93 km Answer

Step 2

Solve:

Since: $\mathrm{\$}=100\text{}\text{cent}\phantom{\rule{0ex}{0ex}}\therefore \mathrm{\$}10.65=10.65\times 100\phantom{\rule{0ex}{0ex}}=1065\text{}\text{cent}$

Now: 12 cans of cost =1065

$\therefore =\frac{1065}{12}=8875\phantom{\rule{0ex}{0ex}}\therefore \text{one can of soup}=8875\phantom{\rule{0ex}{0ex}}\text{our 89 cent}$

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