Find a nonzero vector normal to the plane z?2(x?1)=3(4?y).

Ethen Blackwell

Ethen Blackwell

Answered question

2022-07-27

Find a nonzero vector normal to the plane z?2(x?1)=3(4?y).

Answer & Explanation

Urijah Hahn

Urijah Hahn

Beginner2022-07-28Added 13 answers

plane ---> z- 2(x- 1)=3(4-y)
z - 2x +2 = 12 -3y
-2x + 3y + z =10 is the plane equation
if ax + by + cz = d is an equation of plane then ai + bj +ck is the normal vector of the plane.. so here
normal vector = -2 i + 3 j + k
Nash Frank

Nash Frank

Beginner2022-07-29Added 10 answers

z- 2(x-1)=3(4-y)
=>2x-3y-z+10=0
in general plane =ax+by+cz+d=0
Here (a,b,c) are the direction ratios of the normal to the plane..
so (2,-3,-1) is one of the direction ratio.so the normal vector= K(2,-3,-1) where k belongs to R

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