wstecznyg5

2022-07-28

Given $f(x)=3{x}^{2}-4x-1$ and $g(x)=8-2x$, find each of the following:

a) f(2)

b) f(-2)

c) g(1/4)

a) f(2)

b) f(-2)

c) g(1/4)

Lillianna Mendoza

Beginner2022-07-29Added 16 answers

Step 1

Given: $f(x)=3{x}^{2}-4x-1$

$g(x)=8-2x$

a) $f(2)=?$

$f(x)=3{x}^{2}-4x-1$

$\Rightarrow f(2)=3\times {2}^{2}-4\times 2-1$

$=12-8-1$

$=12-9$

Answer: $=3$

b) $f(-2)=?$

$\Rightarrow f(x)=3{x}^{2}-4x-1$

$f(-2)=3(-2{)}^{2}-4\times (-2)-1$

$=12+8-1$

$=20-1$

Answer: $=19$

c) $g(1/4)=?$

$\Rightarrow g(x)=8-2x$

$g(1/4)=8-\text{\u29f8}2x\frac{1}{\text{\u29f8}{4}_{2}}$

Answer: $=8-\frac{1}{2}=\frac{15}{2}$

Given: $f(x)=3{x}^{2}-4x-1$

$g(x)=8-2x$

a) $f(2)=?$

$f(x)=3{x}^{2}-4x-1$

$\Rightarrow f(2)=3\times {2}^{2}-4\times 2-1$

$=12-8-1$

$=12-9$

Answer: $=3$

b) $f(-2)=?$

$\Rightarrow f(x)=3{x}^{2}-4x-1$

$f(-2)=3(-2{)}^{2}-4\times (-2)-1$

$=12+8-1$

$=20-1$

Answer: $=19$

c) $g(1/4)=?$

$\Rightarrow g(x)=8-2x$

$g(1/4)=8-\text{\u29f8}2x\frac{1}{\text{\u29f8}{4}_{2}}$

Answer: $=8-\frac{1}{2}=\frac{15}{2}$

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