Determine: 27 x 2 − 39 x − 10 3 ( x 2 − 3 x + 5 ) − 2 ( x 2 − 2 x + 1 ) 4 5 y + 1 4 ( y − 5 ) = y + 1 8

Question

Determine:  27      x    2    −  39  x  −  10    3  (      x    2    −  3  x  +  5  )  −  2  (      x    2    −  2  x  +  1  )        4    5    y  +      1    4    (  y  −  5  )  =  y  +      1    8

Reinfarktq6 · Accepted Answer

Step 1  27      x    2    −  39  x  −  10  =  (  9  x  +  2  )  (  3  x  −  5  )    9  x  +  2  =  0    9  x  =  −  2    x  =  −      2    9      3  x  −  5  =  0    3  x  =  5    x  =      5    3  Step 2  3  (      x          2        −  3  x  +  5  )  −  2  (      x    2    −  2  x  +  1  )    3      x    2    −  9  x  +  14  −  2      x    2    +  4  x  −  2    =      x    2    −  5  x  +  12 which is not factorable so we use the quadratic equation  x  =            5      ±              25        −        (        4        )        (        12        )                    2      (      1      )        =            5      ±              25        −        48              2    =      5    2    ±            r              23              2

Determine: 27x^2-39x-10, 3(x^2-3x+5)-2(x^2-2x+1), 4/5y+1/4(y-5)=y+1/8

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