(1) write the equation of the line that contains the indicated pair of points in slope intercept form, (2) write the equation of the line that contains the indicated pair of points in standard form, (3) write the equation of the line that is parallel to the line in parts (1) and (2) and that goes through the point (3, 1) in slope-intercept form, and (4) write the equation of the line that is perpendicular to the line in parts (1) and (2) and that goes through the point (3, 1) in slope-intercept form.(-2,6) and (4,-2)

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Cindy Walls · Accepted Answer

Step 1Points are (-2,6) and (4,-2)Slope (m)   =                    y        2            −              y        1                            x        2            −              x        1              =            −      2      −      6              4      −      (      −      2      )        =            −      8        6        m    1    =            −      4        3  1) Slope intercept form [through (-2,6)]  y  −      y    1    =      m    1    (  x  −      x    1    )  y  −  6  =            −      4        3    (  x  +  2  )  y  −  6  =            −      4        3    x  −            −      8        3    y  =            −      4        3    x  +      10    3  2) In standard form  y  −  6  =  −      4    3    (  x  +  2  )    3  y  −  18  =  −  4  x  −  8    4  x  +  3  y  −  10  =  0Step 23) Parallel to given line and passed through (3,1)Slope       m    1    =      m    2          m    2    =            −      4        3  Equation is  y  −      y    1    =      m    2    (  x  −      x    1    )    y  −  1  =            −      4        3    (  x  −  3  )    y  −  1  =            −      4        3    x  +  4    y  =            −      4        3    x  +  4    y  =            −      4        3    x  +  54) Perpendicular to given line point (3,1)      m    1        m    2    =  −  1  ∴      m    2    =      3    4    ∴  y  −  1  =      3    4    (  x  −  3  )    y  −  1  =      3    4    x  −      9    4      y  =      3    4    x  −      5    4

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