The intensity I of light varies inversely with the square of the distance d from the source, expressed in the equation l=k/d^2. If the intensity is 1/2 of a candela 16 feet from the source, what is the constant of proportionality A. 256 candela- square- feet B. 32 candela- square- feet C. 2 candela- square- feet D. 128 candela- square- feet

lexi13xoxla

lexi13xoxla

Answered question

2022-08-04

The intensity I of light varies inversely with the square of the distance d from the source, expressed in the equation l=k/d^2. If the intensity is 1/2 of a candela 16 feet from the source, what is the constant of proportionality
A. 256 candela- square- feet
B. 32 candela- square- feet
C. 2 candela- square- feet
D. 128 candela- square- feet

Answer & Explanation

neglegir86

neglegir86

Beginner2022-08-05Added 12 answers

I=k/d^2. If the instensity is 1/2 of a candela 16ft from the source, what is the constant of proportionality?
solve I = k / d^2 for k by multiplying both sides of = by d^2
k = I * d^2
now I = 1/2 and d = 16, soooooooo
k = 1/2 * 16^2
k = 1/2 * 256
k = 128 candela-square-feet
so the answer is D

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