Okay I think I'm just having a major brain block, but I need help solving this proportion for my physics class. (6.0xx10^(-6))/(x^2}=(2.0xx10^(-6))/((x-20)^2} What's confusing me is the solution manual to this problem lists writing the proportion as, ((x-20)^2)/(x^2)=(2.0xx10^(-6))/( 6.0xx10^(-6)) and then proceeds to solve the problem from there... but that doesn't seem right to me. Usually you would cross multiply a proportion and solve, but they seemed to do some illegal math or something. Could you guys work me through how to solve this? This answer is 47 by the way.

allucinemsj

allucinemsj

Open question

2022-08-18

How to solve this proportion
Okay I think I'm just having a major brain block, but I need help solving this proportion for my physics class.
6.0 × 10 6 x 2 = 2.0 × 10 6 ( x 20 ) 2
What's confusing me is the solution manual to this problem lists writing the proportion as,
( x 20 ) 2 x 2 = 2.0 × 10 6 6.0 × 10 6
and then proceeds to solve the problem from there... but that doesn't seem right to me. Usually you would cross multiply a proportion and solve, but they seemed to do some illegal math or something. Could you guys work me through how to solve this? This answer is 47 by the way.

Answer & Explanation

Gillian Howell

Gillian Howell

Beginner2022-08-19Added 17 answers

It's only 47 in physics. In mathematics, it would be
20 3 3 1 = 47.320
Anyway: You start off with a proportion that can be written, generally, as
a b = c d
The book then proceeds to rewrite this as
d b = c a
That the two are equivalent (provided a 0) can be seen by multiplying both sides of the first equation by d, and then dividing by a. You can also see that both equations yield the same result after cross-multiplication.
wendi1019gt

wendi1019gt

Beginner2022-08-20Added 7 answers

The proportion they gave is correct. Simply divide both sides of the equation you started with by 6 10 6 and multiply both sides by ( x 20 ) 2
So we have
( x 20 ) 2 x 2 = 2.0 10 6 6.0 10 6 = 1 3 .
The left-hand side becomes
( x 20 ) 2 x 2 = x 2 40 x + 400 x 2 = 1 3 .
Multiplying both sides by x 2 , we get
x 2 40 x + 400 = x 2 3 2 3 x 2 40 x + 400 = 0.
From here you use the quadratic equation to give you x = 10 ( 3 ± 3 ). It's physics, so you probably want the positive one, so x = 10 ( 3 + 3 ) 47.

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