On fraction of products Consider 1/(101)=0.00990099…and 1/(143)=0.00699300699300… and 1/(101xx143)=0.0000692376930000692376930000…. Now 990xx69930=69230700 which is almost 69237693. Is it possible to get exact equality? If so when should I truncate the fractions before multiplying?

mentare9q

mentare9q

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2022-08-30

On fraction of products
Consider 1 101 = 0.00990099 and 1 143 = 0.00699300699300 and 1 101 × 143 = 0.0000692376930000692376930000
Now 990 × 69930 = 69230700 which is almost 69237693
Is it possible to get exact equality? If so when should I truncate the fractions before multiplying?

Answer & Explanation

Alison Mcgrath

Alison Mcgrath

Beginner2022-08-31Added 9 answers

No. You ask whether it is possible to have
a 10 n 1 b 10 m 1 = a b 10 k 1 .
Except for the trivial cases a = 0 or b = 0, this would require
10 k 1 = ( 10 n 1 ) ( 10 m 1 ) = 10 n + m 10 n 10 m + 1.
As the left is 1 ( mod 10 ) and the right + 1 ( mod 10 ), this cannot happen.

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