Find the value of sin ⁡ 24 x cos ⁡ 18 x cos ⁡ 6 x Given tan ⁡ x = 5 − 2, find the value of sin ⁡ 24 x cos ⁡ 18 x cos ⁡ 6 x .Now I wrote numerator as sin ⁡ ( 18 + 6 ) x and I used identity sin ⁡ ( A + B ), after that I reduced problem to tan ⁡ 18 x + tan ⁡ 6 xHow do I proceed? Thanks

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Find the value of             sin      ⁡      24      x              cos      ⁡      18      x      cos      ⁡      6      x      Given   tan  ⁡  x  =      5    −  2, find the value of            sin      ⁡      24      x              cos      ⁡      18      x      cos      ⁡      6      x        .Now I wrote numerator as   sin  ⁡  (  18  +  6  )  x and I used identity   sin  ⁡  (  A  +  B  ), after that I reduced problem to   tan  ⁡  18  x  +  tan  ⁡  6  xHow do I proceed? Thanks

barene55d · Accepted Answer

tan  ⁡  2  x  =            2      (              5            −      2      )              1      −      (              5            −      2              )        2              =      1    2    ,which gives  sin  ⁡  4  x  =      1          1      +              1        4              =      4    5    .

Ayanna Goodman · Accepted Answer

We have                    tan        ⁡        2        x                            =                              2            tan            ⁡            x                                1            −                          tan              2                        ⁡            x                                                            =                              2            (                          5                        −            2            )                                1            −            (                          5                        −            2                          )              2                                                                        =                              2            (                          5                        −            2            )                                1            −            5            +            4                          5                        −            4                                                            =                              2            (                          5                        −            2            )                                4            (                          5                        −            2            )                                                            =                  1          2                    Then use  tan  ⁡  3  A  =            3      tan      ⁡      A      −              tan        3            ⁡      A              1      −      3              tan        2            ⁡      A      to deduce that  tan  ⁡  6  x  =      11    2  Use it once again to deduce that  tan  ⁡  18  x  =      1199    718

Find the value of sin24x/(cos18xcos6x). Given tanx=sqrt(5)−2, Now I wrote numerator as sin(18+6)x and I used identity sin(A+B), after that I reduced problem to tan18x+tan6x How do I proceed? Thanks

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