Thomas stands on a street corner tossing a coin. He decides he will toss the coin 10​ times, each time walking 1 block north if it lands heads​ up, and 1 block south if it lands tails up. Find the probability that he ends up 6 blocks south of6 blocks south of his original corner.

Alice Chen

Alice Chen

Answered question

2022-11-18

Thomas stands on a street corner tossing a coin. He decides he will toss the coin 10​ times, each time walking 1 block north if it lands heads​ up, and 1 block south if it lands tails up. Find the probability that he ends up 6 blocks south of6 blocks south of his original corner.

Answer & Explanation

Arely Davila

Arely Davila

Beginner2022-11-19Added 17 answers

The basic pattes is N N N N N S S S S S to get you to the 6 South end point.
These 5N moves can occue in 10C5
= 252  ways
Each of these 252 pattens her probability
= ( 1 2 ) 10 = 1 1024 Probability  = 252 1024 = 10 C 5 × ( 1024 ) = 0.246

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?