List all injective functions from [2] to [3]. List all surjective functions from [3] to [2] . List all bijective functions from [2] to [2] . Give a relation that is not a function between [2] and [2] and prove that it is not a function.

chiodaiokaC

chiodaiokaC

Answered question

2022-11-23

List all injective functions from [ 2 ] to [ 3 ].
List all surjective functions from [ 3 ] to [ 2 ] .
List all bijective functions from [ 2 ] to [ 2 ] . Give a relation that is not a function between [ 2 ] and [ 2 ] and prove that it is not a function.

Answer & Explanation

elcotevgs

elcotevgs

Beginner2022-11-24Added 10 answers

Step 1
Let A be a set of cardinal k, and B a set of cardinal n.
The number of injective applications between A and B is equal to the partial permutation: n ! ( n k ) !
= 3 ! 1 ! = 6
The number of surjections between the same sets is k ! S ( n , k ) k ! S ( n , k ) where S ( n , k ) S ( n , k ) denotes the Stirling number of the second kind.
A surjection between A and B defines a parition of A in c a r d ( B ) = k c a r d ( B ) = k groups, each group being mapped to one output point in B. The number of such partitions is given by the Stirling number of the second kind. Each permutation of these kk defines a different surjection, hence the k! factor.

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