A stone is flung 20 meters per second in a vertical upward motion. How high will it climb before starting to descend? ( g = 9.8 m / s 2 )

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A stone is flung 20 meters per second in a vertical upward motion. How high will it climb before starting to descend?   (  g  =  9.8  m      /        s    2    )

poly3E7V · Accepted Answer

Given:Initial velocity   u  =  +  20  m      /    sFind velocity   v  =  0  m      /    sAcceleration due to gravity   =  g  =  a  =  9.8  m      /        s    2  To find: Height reached by the stone   =  s  =  ?The third equation of motion yields,      v    2    −      u    2    =  2 as      0    2    −  (  +  20      )    2    =  2  ×  9.8  ×  s  −  400  =  2  ×  9.8  ×  s  s  =  −  400      /    (  2  ×  9.8  )  =  −  20.4  mThe negative sign indicates the opposite direction of displacement and gravity acceleration.The stone&#039;s height as a result   =  20.4  m.

A stone is flung 20 meters per second in a vertical upward motion. How high will it climb before starting to descend? (g=9.8 m/s2)

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