what is the following sum? 1/1*2+1/2*3+1/3*4+...+1/(n-1)*1

autreimL8

autreimL8

Answered question

2022-12-03

what is the following sum?
1 1 2 + 1 2 3 + 1 3 4 + . . . + 1 ( n 1 ) n

Answer & Explanation

Teagan Gamble

Teagan Gamble

Beginner2022-12-04Added 8 answers

This can be written as
2 n 1 n ( n 1 )
Let n = 2
we have sum = 1/2 * 1/1 = 1/2
1/( n ( n-1) ) can be written as 1/n-1 - 1/n
Thus the entire expression can be written as
1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + .... + 1/( n-1) - 1/n
We only have first and last term left
Sum : 1 - 1/n
= ( n-1 ) / n
Answer : n 1 n
nuseldW4r

nuseldW4r

Beginner2022-12-05Added 1 answers

This can be written as
1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + .... + 1/( n-1) - 1/n
= 1 - 1/n
= ( n-1) / n

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