P_1(x)=3x^2+10x+8 and P_2(x)=x^3+x^2+2x+t are two polynomials.When one of the factors of P_1(x) divides P_2(x), 2 is the remainder obtained. That factor is also a factor of the polynomial P_3(x)=2(x+2). Find the value of ‘t’.

ddioddefn5cw

ddioddefn5cw

Answered question

2023-02-22

P 1 ( x ) = 3 x 2 + 10 x + 8 P 2 ( x ) = x 3 + x 2 + 2 x + t
are two polynomials.
When one of the factors of P 1 ( x ) divides P 2 ( x ) , 2 is the remainder obtained.
That factor is also a factor of the polynomial P 3 ( x ) = 2 ( x + 2 )
Find the value of ‘t’.

Answer & Explanation

Haleigh Russo

Haleigh Russo

Beginner2023-02-23Added 6 answers

Let the factor be (x-a).
Using factor theorem, P 3 ( a ) = 0
P 3 ( x ) = 2 ( x + 2 ) P 3 ( a ) = 2 ( a + 2 ) = 0 a = 2
So, the factor is ( x + 2 ) . Verifying that this is also a factor of P 1 ( x ) using factor theorem,
P 1 ( 2 ) = 3 × ( 2 ) 2 + 10 × ( 2 ) + 8 P 1 ( 2 ) = 3 × 4 20 + 8 = 0
By remainder theorem, when P 2 ( x ) is divided by (x+2), the remainder is P 2 ( 2 )
P 2 ( 2 ) = ( 2 ) 3 + ( 2 ) 2 + 2 × ( 2 ) + t P 2 ( 2 ) = 8 + 4 4 + t = t 8
Given remainder is 2. So,
P 2 ( 2 ) = 2 t 8 = 2 t = 10

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