Ashtyn Duncan

2023-02-28

What is the length of an arc which subtends angle θ (degrees) at the centre in a circle of radius r?

$A.(\pi r\theta )/180\phantom{\rule{0ex}{0ex}}B.(\pi r\theta )/360\phantom{\rule{0ex}{0ex}}C.(\pi r\theta )/60\phantom{\rule{0ex}{0ex}}D.(\pi r\theta )/90$

$A.(\pi r\theta )/180\phantom{\rule{0ex}{0ex}}B.(\pi r\theta )/360\phantom{\rule{0ex}{0ex}}C.(\pi r\theta )/60\phantom{\rule{0ex}{0ex}}D.(\pi r\theta )/90$

unieventos8l9

Beginner2023-03-01Added 5 answers

For a slant of ${360}^{\circ}$ subtended at the centre, the arc length is nothing but the circumference of circle that is 2πr where r is circle radius. For a slant of θ, the arc length will be $\frac{\theta}{360}\times 2\pi r=\frac{\theta}{180}\times \pi r$.

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