Sketch the graph of the function a) f(1)=[[1]]+[[−1]]=1±1=0 f(0)=0 f(12)=0±1=−1 f(−2.7)=−3+2=−1 b) limx→1f(x)=−1 limx→1+f(x)=−1 limx→12f(x)=−1 c) f is continuous for all real numbers except 0,±1,±2,±3,±4⋯

a)f(1)=0, f(−1)=0, f(12)=−1,f(−2.7)=−1 b) limx→1−1f(x)=−1,limx→1+=−1,limx→12f(x)=−1 c) f is continuous in R−{n}n :integer.

Question: "Sketch the graph of the function a) f(1)=[[1]]+[[−1]]=1±1=0..."

Amari Flowers

2021-05-16

Sketch the graph of the function
a) $f (1) = [[1]] + [[- 1]] = 1 \pm 1 = 0$

$f (0) = 0$

$f (\frac{1}{2}) = 0 \pm 1 = - 1$

$f (- 2.7) = - 3 + 2 = - 1$

b) $lim_{x \to 1} f (x) = - 1$

$lim_{x \to 1 +} f (x) = - 1$

$lim_{x \to \frac{1}{2}} f (x) = - 1$

c) f is continuous for all real numbers except $0, \pm 1, \pm 2, \pm 3, \pm 4 \dots$

izboknil3

Skilled2021-05-17Added 99 answers

a) $f (1) = 0, f (- 1) = 0,$

$f (\frac{1}{2}) = - 1, f (- 2.7) = - 1$

b) $lim_{x \to 1^{- 1}} f (x) = - 1, lim_{x \to 1^{+}} = - 1, lim_{x \to \frac{1}{2}} f (x) = - 1$
c) f is continuous in $R - {n} n$ :integer.

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