Given that \csc(\theta)=\frac{-\sqrt{5}}{2} and \theta is in Quadran

Kyran Hudson

Kyran Hudson

Answered question

2021-08-20

Given that csc(θ)=52 and θ is in Quadrant 4, what is tan(θ)

Answer & Explanation

toroztatG

toroztatG

Skilled2021-08-21Added 98 answers

Given csc(θ)=52
We know that in 4 Quadrant only cosθ,secθ
So from equation
sinθ=25
cos2θ=1sin2θ=1(25)2
=145=545=15
cos2θ=±15=+15
tanθ=sinθcosθ=2515=2
tanθ=2
Jeffrey Jordon

Jeffrey Jordon

Expert2021-12-11Added 2605 answers

Answer is given below (on video)

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