Find all solution of the equation in the interval [0,2\pi].

Marvin Mccormick

Marvin Mccormick

Answered question

2021-08-14

Find all solution of the equation in the interval [0,2π].
sin2x(csc2x2)=0

Answer & Explanation

berggansS

berggansS

Skilled2021-08-15Added 91 answers

sin2x(csc2x2)=0
So. for the solution of the equation
sin2x=0
2x=arcsin(0)
2x=180 or 2x=π
x=π2
Or
2x=2π
x=π
x=π2 or π
Similiarly,
csc2x2=0
csc2x=2
2x=arccos(2)
2x=π6 or 2x=ππ6
So, xπ12 or 5π12
Jeffrey Jordon

Jeffrey Jordon

Expert2021-12-10Added 2605 answers

Answer is given below (on video)

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