Verify for any integer n: \cos\frac{(2n-1)\pi}{2}=0. Be sure to include a

Annette Arroyo

Annette Arroyo

Answered question

2021-08-17

Verify for any integer n: cos(2n1)π2=0. Be sure to include an explanation of potential cases that may exist with the value of n.

Answer & Explanation

SchulzD

SchulzD

Skilled2021-08-18Added 83 answers

This is question related trigonometry basic problem
cos(2n1)π2
cos(2n212)π
cos(nππ2)
if n is even
then cos(nπ0)=cosθ
then cos(nππ2)=cos(π2)=0
if n is odd
then cos(nπθ)=cosθ
hence cos(nππ2)=cosπ2=0
hence we can say that
cos(2n12)π=0 for all integral values of n" на "This is question related trigonometry basic problem
cos(2n1)π2
cos(2n212)π
cos(nππ2)
if n is even
then cos(nπ0)=cosθ
then cos(nππ2)=cos(π2)=0
if n is odd
then cos(nπθ)=cosθ
hence cos(nππ2)=cosπ2=0
hence we can say that
cos(2n12)π=0 for all integral values of n
Verify for some integral value of "n"
for n=1 cos(ππ2)=cos(π2)=0
for n=2 cos(2ππ2)=cos(3π2)=0
for n=3 cos(3ππ2)=cos(π2)=0
Jeffrey Jordon

Jeffrey Jordon

Expert2021-12-10Added 2605 answers

Answer is given below (on video)

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