Generalize the pattern that emerges by writing down an identity for (x-1)(x^n+x^{n-1}+...+x^2+x+1) for n a positive integer.

ruigE

ruigE

Answered question

2021-09-15

Multiply the polynomials (x1)(x4+x3+x2+x+1) using a table. Generalize the pattern that emerges by writing down an identity for (x1)(xn+xn1++x2+x+1) for n a positive integer.

Answer & Explanation

Nichole Watt

Nichole Watt

Skilled2021-09-16Added 100 answers

To multiply the polynomials, (x1)(x4+x3+x2+x+1), use the distributive property and simplify further by combining the like terms as shown below,
(x1)(x4+x3+x2+x+1)
=x(x4+x3+x2+x+1)1(x4+x3+x2+x+1)
=x5+x4+x3+x2+xx4x3x2x1
=x51
So, on multiplying the polynomials we get x51
Now, generalizing pattern for any positive integer n, the identity obtained by multiplying the polynomials
(x1)(xn+xn1++x2+x+1)
is given by the expression, xn+11

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