For the function defined as follows, find the Taylor polynomials of degree 4 at 0. f(x)=e^{x+1}

Elleanor Mckenzie

Elleanor Mckenzie

Answered question

2021-09-01

For the function defined as follows, find the Taylor polynomials of degree 4 at 0.
f(x)=ex+1

Answer & Explanation

nitruraviX

nitruraviX

Skilled2021-09-02Added 101 answers

The function is, f(x)=ex+1
The Taylor polynomials of degree 4 at 0 is,
P4(x)=f(0)+f(0)1!x+f(0)2!x2+f(3)(0)3!x3=f(4)(0)4!x4
Find the value of f(x) at x=0 as,
f(0)=e0+1
=e1
=e
Find the first, second, third and fourth derivatives of f(x) and find its corresponding values at x=0 as shown in below table.
Derivative of function, f(x)=ex+1Value of derivative at x=0f(x)=ex+1f(0)=e0+1=ef(x)=ddx(f(x))=ddx(ex+1)=ex+1f(0)=e0+1=ef(3)(x)=ddx(f(x))=ddx(ex+1)=ex+1f(3)(0)=e0+1=ef(4)(x)=ddx(f(3)(x))=ddx(ex+1)=ex+1f(4)(0)=e0+1=e
The Taylor polynomials of degree 4 at 0 is calculated as follows.
P4(x)=f(0)=f(0)1!x+f(0)2!x2+f(3)(0)3!x3+f(4)(0)4!x4
=e+e1x+e2x2+e6x3+e24x4

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