Determine the third and fourth Taylor polynomials of x^3+3x-1 at x=-1

bobbie71G

bobbie71G

Answered question

2021-09-13

Determine the third and fourth Taylor polynomials of x3+3x1 at x=1

Answer & Explanation

2k1enyvp

2k1enyvp

Skilled2021-09-14Added 94 answers

To determine the third and fourth Taylor polynomials of
x3+3x1 at x=1
The Taylor series about x=a is given by
f(x)=f(a)+f(a)(xa)+f(a)2!(xa)2+f(a)3!(xa)3+
So, f(x)=x3+3x1
f(x)=3x2+3
f(x)=6x+0
f(x)=6
f4(x)=0Now at x=-1
f(1)=131=5
f(1)=3+3=6
f(1)=6
f(1)=6
f4(1)=0
Therefore, Taylor series at x=-1,
f(1)=(5)+(6)(x+1)+62!(x+1)2+63!(x+1)3+0
The third Taylor Polynomial is T3(x)=5+6(x+1)3(x+1)2
The fourth Taylor polynomial is
T4(x)=5+6(x+1)3(x+1)2+(x+1)3

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