If possible , find 2A−4B A=[−35−63−5−1],B=[−68−336−2] a. [−3042−241814−10] b. not possible c. [100010] d. [−913−961−3] c. [18−220−6−346]

Step 1Considering the matrices providedSince, the order of the matrix A is&nbsp;2×3(2 rows and 3 columns) and also order of the matrix B is&nbsp;2×3The matrices A and B are in the same order in this case.So, subtraction of matrix&nbsp;2A−4B&nbsp;is possible.Step 2Now, find&nbsp;2A−4B.A=[−35−63−5−1],B=[−68−336−2]Now ,&nbsp;2A−4B=2[−35−63−5−1]−4[−68−336−2]Multiply 2 and 4 every element of matrix A and B respectively.=[−610−126−10−2]−[−2432−121224−8]=[−6−(−24)10−32−12−(−12)6−12−10−24−2−(−8)]=[−6+24−22−12+12−6−34−2+8]=[18−220−6−34−6]

"If possible , find 2A−4B A=[−35−63−5−1],B=[−68−336−2] a. [−3042−241814−10]..." solved and explained

foass77W

Answered question

2021-01-10

If possible , find $2 A - 4 B$
$A = [\begin{matrix} - 3 & 5 & - 6 \\ 3 & - 5 & - 1 \end{matrix}], B = [\begin{matrix} - 6 & 8 & - 3 \\ 3 & 6 & - 2 \end{matrix}]$
a. $[\begin{matrix} - 30 & 42 & - 24 \\ 18 & 14 & - 10 \end{matrix}]$
b. not possible
c. $[\begin{matrix} 1 & 0 & 0 \\ 0 & 1 & 0 \end{matrix}]$
d. $[\begin{matrix} - 9 & 13 & - 9 \\ 6 & 1 & - 3 \end{matrix}]$
c. $[\begin{matrix} 18 & - 22 & 0 \\ - 6 & - 34 & 6 \end{matrix}]$

Answer & Explanation

yunitsiL

Skilled2021-01-11Added 108 answers

Step 1
Considering the matrices provided
Since, the order of the matrix A is $2 \times 3$ (2 rows and 3 columns) and also order of the matrix B is $2 \times 3$
The matrices A and B are in the same order in this case.
So, subtraction of matrix $2 A - 4 B$ is possible.
Step 2
Now, find $2 A - 4 B$ .
$A = [\begin{matrix} - 3 & 5 & - 6 \\ 3 & - 5 & - 1 \end{matrix}], B = [\begin{matrix} - 6 & 8 & - 3 \\ 3 & 6 & - 2 \end{matrix}]$
Now , $2 A - 4 B = 2 [\begin{matrix} - 3 & 5 & - 6 \\ 3 & - 5 & - 1 \end{matrix}] - 4 [\begin{matrix} - 6 & 8 & - 3 \\ 3 & 6 & - 2 \end{matrix}]$
Multiply 2 and 4 every element of matrix A and B respectively.
$= [\begin{matrix} - 6 & 10 & - 12 \\ 6 & - 10 & - 2 \end{matrix}] - [\begin{matrix} - 24 & 32 & - 12 \\ 12 & 24 & - 8 \end{matrix}]$
$= [\begin{matrix} - 6 - (- 24) & 10 - 32 & - 12 - (- 12) \\ 6 - 12 & - 10 - 24 & - 2 - (- 8) \end{matrix}]$
$= [\begin{matrix} - 6 + 24 & - 22 & - 12 + 12 \\ - 6 & - 34 & - 2 + 8 \end{matrix}]$
$= [\begin{matrix} 18 & - 22 & 0 \\ - 6 & - 34 & - 6 \end{matrix}]$

Jeffrey Jordon

Expert2022-01-22Added 2605 answers

Answer is given below (on video)

Jeffrey Jordon

Expert2022-08-23Added 2605 answers

Answer is given below (on video)

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