vazelinahS
2021-11-06
Show that the equation has no solutions with integers x and y
i1ziZ
Skilled2021-11-07Added 92 answers
Step 1
To prove: The equation has no integer solutions for x or y
PROOF
Since for all integers and since the equation contains only squares of the unknown integers, it is safe to assume that the integers x and y are nonnegative.
The equation has no differences and the squares are never negative (or negative signs), we only need to check all integers with squares smaller than 14. The only integers with squares smaller than 14 are 0, 1, 2 and 3:
Thus and can take on the values 0, 1, 4 and 9. Let us check if there is a possible combination that makes the equation true.
None of the possible combinations for and made the equation true and thus are no solution in integers x and y such that
Result
To prove it we only need to check for x and y from , because those are only integers which squares are lesser than 14 (assuming that x,y are nonnegative without loss of generality).
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