Solve for x and y [x2y46]=[2−22x−6y] 3[xyyx]=[6−9−96] 2[xyx+yx−y]=[2−4−26] [xy−yx]−[yxx−y]=[4−4−66]

Question

Solve for x and y [x2y46]=[2−22x−6y]  3[xyyx]=[6−9−96]  2[xyx+yx−y]=[2−4−26]  [xy−yx]−[yxx−y]=[4−4−66]

Demi-Leigh Barrera · Accepted Answer

Step 1  Answer(43):  Given that,  [x2y46]=[2−22x−6y]  Two matrices are said to be equal if each corresponding entry is equal. Therefore, equating the corresponding entries of the left and right sides matrice x=2  And  2y=−2  y=−22  y=−1  Hence, the solution of the given equation is x=2, y=-1   Step 2  Answer(44):  Given that,  3[xyyx]=[6−9−96]  Since k[abcd]=[a⋅kb⋅kc⋅kd⋅k]  So , [3x3y3y3x]=[6−9−96]  Two matrices are said to be equal if each corresponding entry is equal.  Therefore, equating the corresponding entries of the left and right sides matrices.  3x=6  x=63  x=2  3y=−9  y=−93  y=−3  Hence, the solution of the given equation is x=2, y=-3  Step 3  Answer(45):  Given that, 2[xyx+yx−y]=[2−4−26]  Since k[abcd]=[a⋅kb⋅kc⋅kd⋅k]  So , [2x2y2(x+y)2(x−y)]=[2−4−26]  Two matrices are said to be equal if each corresponding entry is equal.  Therefore, equating the corresponding entries of the left and right sides matrices  2x=2  x=22  x=1  2y=−4  y=−42  y=−2  Hence, the solution of the given equation is x=1, y=-2  Step 4  Answer(46):  Given that, [xy−yx]−[yxx−y]=[4−4−66]  To find the solution, Apply the matrices property  [abcd]−[pqrs]=[a−pb−qc−rd−s]  [x−yy−x−y−xx=y]=[4−4−66]  Two matrices are said to be equal if each corresponding entry is equal.  Therefore, equating the corresponding entries of the left and right sides matrices.  (1) x-y=4  (2) x+y=6  Now, add the equation (1) and (2).  2x=10  x=5  And, subtract the equation (1) and (2).  −2y=4−6  −2y=−2  y=1  Hence, the solution of the given equation is x=5, y=1

Jeffrey Jordon · Accepted Answer

Answer is given below (on video)

Solve for x and y begin{bmatrix}x & 2y 4 & 6 end{bmatrix}=begin{bmatrix}2 & -2 2x & -6y end{bmatrix} 3begin{bmatrix}x & y y & x end{bmatrix}=begin{bma

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