Serotoninl7
2021-11-13
Geraldine Flores
Beginner2021-11-14Added 21 answers
Define random variable X that marks the number of examine that the pass the student. Also define Y as the random variable that marks whether the student has "on" day or "off" day. We are given that
Suppose that are n examiners, where n is odd natural number. Let's find the distribution of X. Given the information about Y, we know that each examiner will pass student with probabilities 0.8 if Y=1 and 0.4 if Y=0 independently from each other. Hence, given Y, X has binomial distribution with parameters n and appropriate probability of succes. More precisely
Suppose not that n=3. The probability that the student will pass test is
So, we see that the student has higher chances to pass if there are 5 examiners.
Result: He should choose 5 examiners.
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a) .
b) .
c) .
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