permaneceerc
2020-12-29
liannemdh
Skilled2020-12-30Added 106 answers
Step 1
Given statement,
If A and B are
Step 2
This statement is false.
For example, consider
Both are
Then,
Step 3
Since, A+B has eigenvalues 0, 0 and only one linear independent eigenvector corresponding to eigenvalue 0.
So,
A+B is not diagonalizable.
Jeffrey Jordon
Expert2022-01-23Added 2605 answers
Answer is given below (on video)
Jeffrey Jordon
Expert2022-08-23Added 2605 answers
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