solve equation \sin^{2}\theta=-cos2\theta

danrussekme

danrussekme

Answered question

2021-12-01

solve equation
sin2θ=cos2θ

Answer & Explanation

Sculd1987

Sculd1987

Beginner2021-12-02Added 19 answers

Step 1
Calculation:
The given trigonometric equation is sin2(θ)=cos(2θ).
Solve the above equation as follows.
sin2(θ)=cos(2θ)
sin2θ=(12sin2θ)(cos2θ=12sin2θ)
sin2θ+(12sin2θ)=0
sin2θ=1
sin2θ=1
sinθ=1 or sinθ=1
Step 2
Solve the equation θ=sin1(1) as follows.
θ=sin1(1)
=sin1sin(2πn+3π2)
=2πn+3π2
Step 3
Solve the equation θ=sin1(1) as follows.
θ=sin1(1)
=sin1sin(2πn+π2)
=2πn+π2
Step 4
Thus, the solution of the give trigonometric equation is 2πn+3π2 or 2πn+π2

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