Can vectors be inverted in this question? Enquire if it is possible to solve the below for C. B−1(x−μ)=xc Here obviously B is an invertible matrix and both c and μ are column vectors. Would the solution be x−1B−1(x−μ)=c is it possible to invert vectors ? How about if it was the other way B−1(x−μ)=cx Is there any other way to do this ?

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Can vectors be inverted in this question?  Enquire if it is possible to solve the below for C.  B−1(x−μ)=xc  Here obviously B is an invertible matrix and both c and μ are column vectors.  Would the solution be x−1B−1(x−μ)=c is it possible to invert vectors ?  How about if it was the other way  B−1(x−μ)=cx  Is there any other way to do this ?

Bubich13 · Accepted Answer

Vectors, in general, cant

Melissa Moore · Accepted Answer

q=△H, since pressure is constant  △H=∫t1t1(HJ)=∫298473{20.17+0.3665(TK)}d(TK)  =(20.17)×(473−298)+(0.36652)×(TK)2∣298473  =(3.530×103)+(2.4725×104)=2.83×104  q=△H=2.83×104J=+28.3kJ  w=−pcx△V[2,8]. where pex=p  w=−p△V=−△(pV)[constant pressure]=−△(nRT)[perfect gas]=−nR△T  =(−1.00mol)×(8.314JK−1mol−1)×(473K−298K)=−1.45×103J=−1.45kJ  △U=q+w=(28.3kJ)−(1.45kJ)=+26.8kJ  (b) The energy and enthalpy of a perfect gas depend on temperature alone, hence it does not matter whether the temperature change is brought about at constant volume or constant pressure; △H and △U are the same.  △H=+28.3kJ,△U=+26.8kJ  Under constant volume, w=0  q=△U−w=+26.8kJ

nick1337 · Accepted Answer

Perhaps this definition of the inverse vector will help you:An inverse rectilinear vector a→′ is a vector which is co-directed (in the same direction as) a vector a→ and differs from it in magnitude according to: |d―|=1|a―|Projections on the coordinate axes of inverse rectilinear vectors are equal according to:ax‘=axax2+ay2+az2;ay‘=ayax2+ay2+az2az‘=azax2+ay2+az2;

Can vectors be inverted in this question? Enquire if it is possibl

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