Dot product of two perpendicular vectors If V1 and V2 are perpendicular, calculate V1⋅V2. Express your answer in terms of V1 and V2. V1⋅V2=

Dot product of two perpendicular vectors. If V1→ and V2→ are perpendicular: V→1⋅V→2=|V→1||V→2|cos⁡(θ) But θ=90∘. ∴V→1⋅V→2=|V→1||V→2|cos⁡(90) ∴V→1⋅V→2=0

The dot product of two vectors V→1 and V→2 is which are parallel is, V→1⋅V→2=|V→1||V→2|cos⁡90∘ =0 V→1V→2=0

Dot product of two perpendicular vectors. If V1→ and V2→ are perpendicular: V→1⋅V→2=|V→1||V→2|cos⁡(θ) But θ=90∘. ∴V→1⋅V→2=|V→1||V→2|cos⁡(90) ∴V→1⋅V→2=0

The dot product of two vectors V→1 and V→2 is which are parallel is, V→1⋅V→2=|V→1||V→2|cos⁡90∘ =0 V→1V→2=0

Find out the answer to "Dot product of two perpendicular vectors If V1..."

Carol Valentine

Answered question

2021-12-17

Dot product of two perpendicular vectors If

V_{1}

and

V_{2}

are perpendicular, calculate

V_{1} \cdot V_{2}

. Express your answer in terms of

V_{1}

and

V_{2}

V 1 \cdot V 2 =

Answer & Explanation

Lindsey Gamble

Beginner2021-12-18Added 38 answers

It might be 0, am I right?

Stuart Rountree

Beginner2021-12-19Added 29 answers

Dot product of two perpendicular vectors. If

\vec{V_{1}}

and

\vec{V_{2}}

are perpendicular:

{\vec{V}}_{1} \cdot {\vec{V}}_{2} = | {\vec{V}}_{1} | | {\vec{V}}_{2} | \cos (θ)

But

θ = 90^{\circ}

∴ {\vec{V}}_{1} \cdot {\vec{V}}_{2} = | {\vec{V}}_{1} | | {\vec{V}}_{2} | \cos (90)

∴ {\vec{V}}_{1} \cdot {\vec{V}}_{2} = 0

nick1337

Expert2021-12-28Added 777 answers

The dot product of two vectors ${\vec{V}}_{1}$ and ${\vec{V}}_{2}$ is which are parallel is,
${\vec{V}}_{1} \cdot {\vec{V}}_{2} = | {\vec{V}}_{1} | | {\vec{V}}_{2} | \cos 90^{\circ}$
$= 0$
${\vec{V}}_{1} {\vec{V}}_{2} = 0$

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