FSP01511000131.jpgFSZ Part A For the two vectors in

regatamin2

regatamin2

Answered question

2021-12-18


Part A
For the two vectors in the figure (Figure 1) , find the magnitude of the vector product A×B.
Part B
Find the direction of the vector product A×B .
Find the direction of the vector product .
Part C
Find the magnitude of A×B .
Part D
Find the direction of A×B.

Answer & Explanation

Karen Robbins

Karen Robbins

Beginner2021-12-19Added 49 answers

Part A:
A×B=(2.80[cos60x^+sin60y^])×(1.90[cos60x^sin60y^])
=2.80×1.90cos60sin60z^2.80×1.90cos60sin60z^
=2×2.80×1.90cos60sin60z^
=4.61 cm2 z^
Magnitude: =4.61 cm2
Part B:
Direction of A×B is along negative z^ direction.
That's all what I can help for you
Deufemiak7

Deufemiak7

Beginner2021-12-20Added 34 answers

Here is the continuation of the solution:
Part C:
|A×B|=|B×A|=4.61 cm2
Part D:
Since A×B=B×A, direction of B×A is along positive z^ direction
nick1337

nick1337

Expert2021-12-28Added 777 answers

thank you they were all right on pearson!

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?