How does \frac{4\pi x+\cos(4 \pi x)\sin(4 \pi x)}{8\pi}+C become \frac{\sin(8\pi

widdonod1t

widdonod1t

Answered question

2021-12-31

How does 4πx+cos(4πx)sin(4πx)8π+C become sin(8πx)+8πx16π+C?

Answer & Explanation

otoplilp1

otoplilp1

Beginner2022-01-01Added 41 answers

Just use trig identities.
cosxsinx=12sin(2x)
so then you get:
sin(8πx)2+4πx8π+C
which simplifies to:
sin(8πx)+8πx16π+C
Esta Hurtado

Esta Hurtado

Beginner2022-01-02Added 39 answers

Needed Double Angle Identity:
2sin(x)cos(x)=sin(2x)
Vasquez

Vasquez

Expert2022-01-09Added 669 answers

They have simply used the identity 2sin(x)cos(x)=sin(2x) and solved it further

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?