how is this solved? \lim_{x \to 0} \frac{1}{x^2} ((\tan(x+\frac{\pi}{4})^{\frac 1x}-e^2)

ajedrezlaproa6j

ajedrezlaproa6j

Answered question

2022-01-14

how is this solved? limx01x2((tan(x+π4)1xe2)

Answer & Explanation

Esther Phillips

Esther Phillips

Beginner2022-01-15Added 34 answers

We use Taylor series around 0:
tan(x+π4)=1+2x+2x2+83x3+.
Hence, by using Taylor series for the logarithm and the exponential function,
(tan(x+π4))1x=exp(1xlogtan(x+π4))
=exp(1xlog(1+2x+2x2+83x3+))
=exp(1x(2x+43x3+))=e2exp(43x2+)
=e2(1+43x2+)
This yields the limit 43e2

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