Evaluate \lim_{x \to 0} \ln(\frac{\cos x}{1+\sin x})^{\frac 1x}

William Boggs

William Boggs

Answered question

2022-01-17

Evaluate limx0ln(cosx1+sinx)1x

Answer & Explanation

Mary Goodson

Mary Goodson

Beginner2022-01-18Added 37 answers

Using LHopitals Rule, we have
limx0ln(cosx1+sinx)1x=limx0ln(cosx)ln(1+sinx)x
=limx0(tanxcosx1+sinx)
=-1
lalilulelo2k3eq

lalilulelo2k3eq

Beginner2022-01-19Added 38 answers

Hint. Use the fact that lnuv=vlnu and the Taylor expansion for cosx,sinx; then use again the Taylor expansion of ln(1+x).

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