Prove that: \sin \beta \sin(\frac{\pi}{3}-\beta) \sin(\frac{\pi}{3}+\beta)=\frac 14 \sin 3 \beta

Carol Valentine

Carol Valentine

Answered question

2022-01-17

Prove that: sinβsin(π3β)sin(π3+β)=14sin3β

Answer & Explanation

Mary Goodson

Mary Goodson

Beginner2022-01-18Added 37 answers

Firstly I will give you an easy exercise :
sin(A+B)sin(AB)=sin2Asin2B
Hint for the exercise :
Use the formula : cos(A)cos(B)=2sin(A+B2)sin(AB2)
Now, for the question :
sinβsin(π3β)sin(π3+β)
=sinβ(sin2(π3)sin2(β))
=sinβ(34sin2(β))
=sin3β4

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