Solve 2\cos^2 x+\sin x=1 for all possible x

Annette Sabin

Annette Sabin

Answered question

2022-01-15

Solve 2cos2x+sinx=1 for all possible x

Answer & Explanation

usumbiix

usumbiix

Beginner2022-01-16Added 33 answers

2cos2(x)+sin(x)=12(1sinx)(1+sinx)+sinx1=0
(sinx1)(22sinx)+(sinx1)=0(sinx1)(12sinx)=0
which indeed leads to the same solutions, or also from here by t=sinx
22sin2x+sinx=12t2t1=0
t1,2=1±94=1,  12

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