Evaluating \lim_{x \to 0} (\sin x)^x

Connor Randall

Connor Randall

Answered question

2022-01-23

Evaluating limx0(sinx)x

Answer & Explanation

tipoule137p

tipoule137p

Beginner2022-01-24Added 10 answers

Most probably you mean x0+, because for x<0 the expression is not defined for real functions.
Using limt0+tt=1 you get
((sinx)sinx)xsinxx0+11=1

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