Proving \arctan(\sqrt{x^2+1})=\frac{\pi}{4}-\frac{1}{2}\arctan(x)

Journey Stout

Journey Stout

Answered question

2022-01-25

Proving arctan(x2+1)=π412arctan(x)

Answer & Explanation

ma90t66690

ma90t66690

Beginner2022-01-26Added 7 answers

Let θ=arctan(x2+1x), then tanθ=x2+1x and we can easily solve this for x, as
x=1tan2θ2tanθ=cot2θ=tan(π22θ)
which implies
θ=π412arctan(x)

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