If a+b+c=90^{\circ}, prove \tan(a) \cdot \tan(b)+\tan(b) \cdot \tan(c)+\tan(c) \cdot \tan(a)=1

Jamya Elliott

Jamya Elliott

Answered question

2022-01-25

If a+b+c=90, prove tan(a)tan(b)+tan(b)tan(c)+tan(c)tan(a)=1

Answer & Explanation

immablondevl

immablondevl

Beginner2022-01-26Added 11 answers

Writing
tanc=tan(π2(a+b))=1tan(a+b)=1tanatanbtana+tanb
So we have
tanatanb+tanatanc+tanbtanc=tanatanb+tanatan2atanbtana+tanb+tanbtanatan2btana+tanb
=tan2atanb+tanatan2b+tanatan2atanb+tanbtanatan2btana+tanb=tana+tanbtana+tanb=1

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