What can we say about a \cos^2 \theta+b \sin^2 \theta?

Gerald Ritter

Gerald Ritter

Answered question

2022-01-26

What can we say about acos2θ+bsin2θ?

Answer & Explanation

Dakota Cunningham

Dakota Cunningham

Beginner2022-01-27Added 9 answers

Notice that sin2θ+cos2θ=1 then your expression is a weighted mean of a and b.
Eleanor Shaffer

Eleanor Shaffer

Beginner2022-01-28Added 16 answers

Write it as acos2θ+asin2θ+(ba)sin2θ which gives you a+(ba)sin2θ

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