What can we say about a \cos^2 \theta+b \sin^2 \theta?

Gerald Ritter

Gerald Ritter

Answered question


What can we say about acos2θ+bsin2θ?

Answer & Explanation

Dakota Cunningham

Dakota Cunningham

Beginner2022-01-27Added 9 answers

Notice that sin2θ+cos2θ=1 then your expression is a weighted mean of a and b.
Eleanor Shaffer

Eleanor Shaffer

Beginner2022-01-28Added 16 answers

Write it as acos2θ+asin2θ+(ba)sin2θ which gives you a+(ba)sin2θ

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?