Prove \sin(a)<a<\tan(a) when 0<a<\frac{\pi}{2}

spiderifilms6e

spiderifilms6e

Answered question

2022-01-23

Prove sin(a)<a<tan(a) when 0<a<π2

Answer & Explanation

Dominique Green

Dominique Green

Beginner2022-01-24Added 11 answers

For 0a<π2 define
f(a)=asin(a) (1)
g(a)=tan(a)a (2)
From (1), note f(0)=0. For a>0, f(a)=1cos(a)>0 so f(a)>0, giving
sin(a)<a(3)
From (2), g(0)=0. For a>0, g(a)=cos(a)cos(a)+sin2(a)cos2(a)1=sin2(a)cos2(a)>0 so g(a)>0, giving
a<tan(a) (4)
Putting (3) and (4) together gives
sin(a)<a<tan(a) (5)
for 0<a<π2

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