Find the value of the function \cos(\alpha−\beta)/2 I solved it by

licencegpopc

licencegpopc

Answered question

2022-01-25

Find the value of the function cos(αβ)2
I solved it by squaring the two equations such that I get sin2α+sin2β+2sinαsinβ=4414225 And cos2α+cosβ+2cosαcosβ=7294225
Adding them we get 2+2(sinαsinβ+cosαcosβ)=11704225
Then, 1+cos(αβ)=5854225
Therefore cos(αβ)=36404225
So now cos(αβ)2=+or  5858450

Answer & Explanation

jojoann325

jojoann325

Beginner2022-01-26Added 10 answers

5858450=65×98450
=3658450=31130
also your minus comes from αβ[π,3π]
marzembreax

marzembreax

Beginner2022-01-27Added 13 answers

The answer is 3130 because
π2<αβ2<3π2
which gives
cosαβ2<0

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