Simplifying \sqrt{\frac{(a^2 \cos^2 t+b^2 \sin^2 t)^3}{(b^2 \cos^2 t+a^2 \sin^2 t)^3}}

2alr8w

2alr8w

Answered question

2022-01-23

Simplifying (a2cos2t+b2sin2t)3(b2cos2t+a2sin2t)3

Answer & Explanation

Serifluinueyk

Serifluinueyk

Beginner2022-01-24Added 7 answers

Divide both the numerator and denominator by a2+b2, then use a2a2+b2=sin2u. Your expression will become
sin2ucos2t+cos2usin2tcos2ucos2t+sin2usin2t
Now use sin2u+cos2u=1
sin2ucos2t+cos2usin2tcos2ucos2t+sin2usin2t=(1cos2u)cos2t+(1sin2u)sin2tcos2ucos2t+sin2usin2t
=(cos2t+sin2t)(cos2ucos2t+sin2usin2t)cos2ucos2t+sin2usin2t
=1cos2ucos2t+sin2usin2t1

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