Proving \int_0^{\frac{\pi}{4}} \sin^n (x) dx > \frac{1}{2^{n/2}(n+2)}

Jayleen Sanders

Jayleen Sanders

Answered question

2022-01-23

Proving 0π4sinn(x)dx>12n2(n+2)

Answer & Explanation

Amari Larsen

Amari Larsen

Beginner2022-01-24Added 10 answers

I would (optionally) substitute sinx=t and integrate by parts twice:
012tndt(1t2)12=1n+1(tn+1(1t2)12012012tn+2dt(1t2)32)
=1n+1(2n21n+3tn+3(1t2)32012+)
>2n2n+1(11n+3)=2n2n+2(n+2)21>[whatweneed]

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