Show \int^{2\pi}_0 \cos^2 t dt=\pi using Pythagorean Theorem The 'traditional' way I alway

Alvin Pugh

Alvin Pugh

Answered question

2022-01-24

Show 02πcos2tdt=π using Pythagorean Theorem
The traditional way I always see this integral calculated is with the identity
cos2t=1+cos(2t)2
My alternative method uses cos2t+sin2t=1. Its

Answer & Explanation

Eleanor Shaffer

Eleanor Shaffer

Beginner2022-01-25Added 16 answers

Your argument is definitely valid. To add more explanation, we can say that
aa+Tf(x)dx=0Tf(x)dx
for any T-periodic function f(x) (try to prove this rigorously), and then
02πsin2tdt=02πcos2(tπ2)dt=π22ππ2cos2tdt=02πcos2tdt
Telering3b

Telering3b

Beginner2022-01-26Added 11 answers

Use 02af(x)dx=20af(x)dx  for  f(2ax)=f(x)
twice to find
I=02πcos2tdt=40π2cos2tdt
Now abf(x)dx=abf(a+bx)dx
to find
2I4=0π2(cos2t+sin2t)dt

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