If x=a \cos t^3,y=b \sin t^3 then what is \frac{d^3y}{dx^3}?

William Montgomery

William Montgomery

Answered question

2022-01-23

If x=acost3,y=bsint3 then what is d3ydx3?

Answer & Explanation

Fallbasisz8

Fallbasisz8

Beginner2022-01-24Added 9 answers

dividing d3ydt3  by  d3xdt3 never gives d3ydx3. Actual rule is:
d2ydx2=ddx(dydx)=ddx(dydtdxdt)
=xddx(y)yddx(x)(x)2
Where x=dxdt  and  y=dydt
Now d3ydx3=ddx(d2ydx2)

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?